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Assignment #5(b)|
MIE165S Assignment #5(b) Solution
Q#1:
For the tractor retired after 7 years:
Capital Recovery = ($24,000-$8,000)(A/P,8%,7)+8000*0.08 = $3,713
Annual maintenance= $2,000
So total annual cost = $5,713
For the tractor retired after 10 years:
Capital Recovery = ($24,000-$4,500)(A/P,8%,10)+4,500*0.08 = $3,265
Note after the 7th year the maintenance cost becomes $5,000.
So we must find the equibvalent uniform annual maintenance.
We will assume that there is uniform $2,000 for ten years and
there is extra $2000 for the last three years.
So equivalent uniform amount is:
Equivalent uniform annual maintenance
= $2,000+ $2,000 *(F/A,8,3)*(A/F,8,10)
= $2,448
So total annual cost = $5,714
Q#2:
Let X denote the number of days per year that the facility will be in use.
So the annual cost of owning the facility is:
Capital Recovery
= (24,000-1,800)(A/P,15%,4)+1,800*0.15 = $8046,66
Fixed Cost
= $9,200
Operating Cost
= $120X
Total Cost = $17,246.66 + 120X
The total cost of renting the facility is $225X
So the break-even point can be found as follows:
$17,246.66 + 120X = $225X
So, we can find that X= 17,246.66/105 = 164.25 days
(165 days)